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x^2*1/4x=1024
We move all terms to the left:
x^2*1/4x-(1024)=0
Domain of the equation: 4x!=0We multiply all the terms by the denominator
x!=0/4
x!=0
x∈R
x^2*1-1024*4x=0
Wy multiply elements
x^2-4096x=0
a = 1; b = -4096; c = 0;
Δ = b2-4ac
Δ = -40962-4·1·0
Δ = 16777216
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{16777216}=4096$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4096)-4096}{2*1}=\frac{0}{2} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4096)+4096}{2*1}=\frac{8192}{2} =4096 $
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